Thread: Really no pressure during stropping ...?

Originally Posted by 10Pups

Think .00000314 psi.

Is it the same for each style of blade? I was always under the impression you increase it by 3/10ths of a percent for full hollow and decrease by the same for wedges. That is if your are north of the equator, if your south, then.....well I guess your screwed because the formula only works north of the equator.

Originally Posted by Chugach68

Is it the same for each style of blade? I was always under the impression you increase it by 3/10ths of a percent for full hollow and decrease by the same for wedges. That is if your are north of the equator, if your south, then.....well I guess your screwed because the formula only works north of the equator.

I always thought the increase was the other way around for the wedge and hollow,, But I do concur on the N and S of the Equator as per reading our AU friends posts

You only use .00000314 psi pressure for circular honing! Get it!!? I use a little pressure when my strop is flat and taut and no pressure when I add deflection or purposely lift the spin. I think an expert thinks about different stropping strategies and imagines, at least, some differences. I've always thought I could strop for a touch better smoothness if I desired to.

Either way, gentle patience usually pays-off, pressure can bite you back.

yes Glen its very confusing, I understand, but since it is before labor day the increase is as stated.

Originally Posted by MickR

Actually what you have to do is bear down on that bugger like you're trying to drown yer worst enemy before his dog gets to ya!...That, just in case some idiot gets the wrong idea and actually does this, is meant to be a joke!


Mick

Whew, at first I thought you were suggesting drowning his dog ... now that would be cruel!

Originally Posted by Brenngun

Well no not absolute zero (no temperature pun intended). Your answer lies within the laws of friction. Specifically kinetic friction. When one considers the energy expended while stropping one understands that the "law of conservation of energy" means it is lost to the system by transforming into heat.

Simply stated When an object is pushed along a surface, the energy converted to heat is given by:

Attachment 139289

where

Attachment 139290, is the normal force,

Attachment 139291, is the coefficient of kinetic friction,

Attachment 139292, is the coordinate along which the object transverses.

Energy lost to a system as a result of friction is a classic example of thermodynamic irreversibility

This heat of course is used to polish the bevel surface of the razors thereby delivering a smoother shave. You can therefore conclude that some amount of pressure is require.

I hope this clears it up for you.

Ooo, nice. Although I'd never use a roman font for a subscript n or k. Totally reserved for dimensional quantities ;-)

Originally Posted by gssixgun

Telling a newb this, is akin to telling a white belt to perform a Jumping Back Spin kick without ever taking the time to teach him the foundation of how that is accomplished...

Nah, it's okay. I get what Jeff's saying.

So there you have it. The truth the whole truth and everything in between. It is totally unquantifiable. When the direction of the parallelogram is in perpendicular angle such as a bisector. The pressure towards the primary indicator of the level to the bevel is not proportionate to the angular action exerted by the middle joint of the right arm. This is of course only true if you are north of the equator and (what everyone forgot) facing west as the control factor indicates as necessary to perform this function with satisfactory results.

In other words .....Use the force Luke !

And you thought we were going to have a hard time describing this.

Originally Posted by Headcrowny

Nah, it's okay. I get what Jeff's saying.

Glad you do, that lost me at the first turn.

Bob

Originally Posted by BobH

Glad you do, that lost me at the first turn.

Bob

Nahh, ya have to jump first ,then turn & kick.